Python retry with exponential backoff

import time
from functools import wraps

def retry(attempts=3, base_delay=0.25):
    def decorate(function):
        @wraps(function)
        def wrapped(*args, **kwargs):
            for attempt in range(attempts):
                try:
                    return function(*args, **kwargs)
                except TimeoutError:
                    if attempt == attempts - 1:
                        raise
                    time.sleep(base_delay * (2 ** attempt))
        return wrapped
    return decorate